Twelve balls are distribute among three ...

Twelve balls are distribute among three boxes. The probability that the first box contains three balls is `(110)/9(2/3)^(10)` b. `(110)/9(2/3)^(10)` c. `(^(12)C_3)/(12^3)xx2^9` d. `(^(12)C_3)/(3^(12))`

`(110)/(9)((2)/(3))^(10)`

`(9)/(110)((2)/(3))^(10)`

`(""^(12)C_(3))/(12^(3))xx2^(9)`

`(""^(12)C_(3))/(3^(12))`

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