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In a given race the odds in favour of th...

In a given race the odds in favour of three horses A, B, C are 1 : 3, 1 : 4, 1 : 5 respectively. Assuming that dead head is impossible the probability that one of them wins is

A

`(7)/(60)`

B

`(37)/(60)`

C

`(1)/(5)`

D

`(1)/(8)`

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The correct Answer is:
To solve the problem, we need to find the probability that one of the horses A, B, or C wins the race, given the odds in favor of each horse. ### Step-by-Step Solution: 1. **Understanding Odds**: - The odds in favor of a horse represent the ratio of the probability of the horse winning to the probability of it losing. - For horse A, the odds are 1:3, meaning for every 1 time A wins, it loses 3 times. Thus, the total outcomes for A are 1 (win) + 3 (loss) = 4. - Therefore, the probability of A winning (P(A)) is given by: \[ P(A) = \frac{1}{1 + 3} = \frac{1}{4} \] 2. **Calculating Probability for Horse B**: - The odds in favor of horse B are 1:4. So, the total outcomes for B are 1 (win) + 4 (loss) = 5. - Therefore, the probability of B winning (P(B)) is: \[ P(B) = \frac{1}{1 + 4} = \frac{1}{5} \] 3. **Calculating Probability for Horse C**: - The odds in favor of horse C are 1:5. Thus, the total outcomes for C are 1 (win) + 5 (loss) = 6. - Therefore, the probability of C winning (P(C)) is: \[ P(C) = \frac{1}{1 + 5} = \frac{1}{6} \] 4. **Finding the Total Probability**: - Since we are assuming that one of the horses must win (no dead heat), we can add the probabilities of each horse winning: \[ P(\text{one of A, B, or C wins}) = P(A) + P(B) + P(C) \] - Substituting the values we found: \[ P(\text{one of A, B, or C wins}) = \frac{1}{4} + \frac{1}{5} + \frac{1}{6} \] 5. **Finding a Common Denominator**: - The least common multiple (LCM) of 4, 5, and 6 is 60. - Now we convert each fraction: \[ \frac{1}{4} = \frac{15}{60}, \quad \frac{1}{5} = \frac{12}{60}, \quad \frac{1}{6} = \frac{10}{60} \] 6. **Adding the Probabilities**: - Now we can add the converted fractions: \[ P(\text{one of A, B, or C wins}) = \frac{15}{60} + \frac{12}{60} + \frac{10}{60} = \frac{37}{60} \] ### Final Answer: The probability that one of the horses A, B, or C wins the race is: \[ \frac{37}{60} \]
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DISHA PUBLICATION-PROBABILITY-1-EXERCISE-1 : CONCEPT BUILDER
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