Statement-1 : Three natural number are taken at random from the set `A={x:1 lt x lt= 100, x in N}` the probability that the A.M of the numbers taken is 25 is equal to `(""^74C_2)/(""^100C_3)`.
Statement-2 : Let A = {2, 3, 4 …. 20}. A number is chosen at random from set A and it is bound to be a prime number. The probability that it is more than 10 is `1/5`.
Statement-3 : The probability of three person having the same date month for the birthday is `1/((365)^2)`.

Options

A. `(""^(77)C_(2))/(""^(100)C_(3))`
B. `(""^(25)C_(2))/(""^(100)C_(3))`
C. `(""^(74)C_(72))/(""^(100)C_(97))`
D. None of these

Answer

C