A student measures the time period of `100` ocillations of a simple pendulum four times. The data set is `90 s`, 91 s, 95 s, and 92 s`. If the minimum division in the measuring clock is `1 s`, then the reported men time should be:

Options

A. `92 pm 1.8s`
B. `92 pm 3s`
C. `92 pm 2s`
D. `92 pm 5.0s`

Answer

C

Explanation

`DeltaT=(|DeltaT_(1)|+|DeltaT_(2)|+|DeltaT_(3)|+|DeltaT_(4)|)/(4)=(2+1+3+0)/(4)=1.5`
As the resolution of measuring clock is 1.5 therefore the mean time should be `92 pm 1.5`