Dimensions of `ohm` are same as that of (where h is Planck's constant and e is charge)

Options

A. `(h)/(e)`
B. `(h^(2))/(e)`
C. `(h)/(e^(2))`
D. `(h^(2))/(e^(2))`

Answer

C

Explanation

`(h)/(e^(2))=(ML^(2)T^(-1))/((AT)^(2))=ML^(2)T^(-3)A^(-2)="Resistance (ohm)"`