The velocity v of a particle at time t is given by `v=at+b/(t+c)`, where a, b and c are constants. The dimensions of a, b, c are respectively :-

Options

A. `[LT^(-2)],[L],[T]`
B. `[L^(2)], [T] and [LT^(2)]`
C. `[LT^(2)], [LT] and [L]`
D. `[L], [LT] and [T^(2)]`

Answer

A

Explanation

As c is added to t, `therefore" "c=[T]`
`a=(v)/(t)=(LT^(-1))/(T)=[LT^(-2)]`,
`b=v(t+c)=LT^(-1)xxT=[L]`