The displacement 'x' (in meter) of a particle of mass 'm' (in kg) moving in one dimension under the action of a force is released to time 't' (in sec) by `t = sqrt(x) + 3`. The displacement of the particle when its velocity is zero will be.

Options

A. 2m
B. 4m
C. zero
D. 6m

Answer

C

Explanation

`:. t= sqrtx + 3`
`rArr sqrtx= t-3 rArr x= (t-3)^(2)`
`v= (dx)/(dt) = 2 (t-3) = 0 rArr t= 3`
`:. x= (3-3)^(2) rArr x= 0`