A particle is moving with uniform acceleration along a straight line. The average velocity of the particle from P to Q is `8ms^(-1)` and that Q to S is `12ms^(-1)`. If QS= PQ, then the average velocity from P to S is

Options

A. `9.6ms^(-1)`
B. `12.87ms^(-1)`
C. `64ms^(-1)`
D. `327ms^(-1)`

Answer

A

Explanation

`8 = (x)/(t_(1)), 12 = (x)/(t_(2))`
`bar(v) = (2x)/(t_(1) + t_(2)) = (2x)/((x)/(8) + (x)/(12)) = (2 xx 8 xx 12)/(12 + 8) = 9.6 ms^(-1)`