A particle experiences a constant acceleration for 20 sec after starting from rest. If it travels distance `S_1` in the first 10 sec and a distance `S_2` in the next 10 sec, Then

Options

A. `s_(2) = s_(1)`
B. `s_(2) = 2s_(1)`
C. `s_(2) = 3s_(1)`
D. `s_(2) = 4s_(1)`

Answer

C

Explanation

Let a be the constant acceleration of the particle. Then `s= u t + (1)/(2) a t^(2) or s_(1) = 0 + (1)/(2) xx a xx (10)^(2) = 50a and s_(2) = [0 + (1)/(2) a (20)^(2)] -50a = 150a`
`:. s_(2) = 3s_(1)`