The distance travelled by a particle starting from rest and moving with an acceleration `(4)/(3) ms^-2`, in the third second is.

Options

A. 6m
B. 4m
C. `(10)/(3)m`
D. `(19)/(3)m`

Answer

C

Explanation

Distance travelled in the nth second is given by
`d=u + (a)/(2) (2n-1)`
put `u= 0, a= (4)/(3) ms^(-2),n=3`
`:. d= 0 + (4)/(3 xx 2) (2 xx 3 -1) = (4)/(6) xx 5 = (10)/(3)m`