A ball is thrown vertically upwards with a speed of `10 m//s` from the top of a tower 200 m height and another is thrown vertically downwards with the same speed simultaneously. The time difference between them on reaching the ground is `(g=10 m//s^(2))`

Options

A. 12s
B. 6s
C. 2s
D. 1s

Answer

C

Explanation

The ball thrown upward will lose velocity in 1s. It return back to thrown point in another 1s and the same velocity as second. Thus the difference will be 2s.