Two boys are standing at the ends A and B of a ground, where `AB=a`. The boy at B starts running in a direction perpendicular to AB with velocity `v_(1)`. The boy at A starts running simultaneously with velocity v and catches the other boy in a time t, where t is :

Options

A. `a^2/sqrt(v^2+v_1^2)`
B. `a^2/(v^2-v_1^2)`
C. `a^2/(v^2+v_1^2)`
D. `sqrt(a^2/(v^2-v_1^2))`

Answer

D