A projectile is thrown at an angle of `40^(@)` with the horizontal and its range is `R_(1)`. Another projectile is thrown at an angle of `40^(@)` with the vertical and its range is `R_(2)`. What is the relation between `R_(1)` and `R_(2)` ? (projection speed is same in both cases)

Options

A. `R_1=R_2`
B. `R_1=2R_2`
C. `2R_1=R_2`
D. `R R_1=4R_2//5`

Answer

A

Explanation

R is same for both `theta` and `(90-theta)` . If angle w.r.t. vertical is `40^@` then w.r.t. horizontal direction it will be `90^@-40^@=50^@`