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The equation of a projectile is y=sqrt(3...

The equation of a projectile is `y=sqrt(3)x-(gx^(2))/(2)`
the angle of projection is:-

A

`tan theta = 1/sqrt3`

B

`tan theta = sqrt3 `

C

`pi/2`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B
Comparing the given equation with
`y=x tan theta - (gx^2)/(2u^2 cos^2 theta)`, we get tan `theta =sqrt3`
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DISHA PUBLICATION-MOTION IN A PLANE -Exercise -1 : CONCEPT BUILDER (TOPICWISE)
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