A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone up to will be:

Options

A. `20sqrt2` m
B. 10m
C. `10sqrt2` m
D. 20m

Answer

D

Explanation

`R=(u^2 sin^2 theta)/g , H=(u^2 sin^2 theta)/(2g)`
`H_"max"` at `2theta=90^@`
`H_(max)=u^2/(2g)`
`u^2/(2g)=10 rArr u^2 =10gxx2`
`R=(u^2 sin 2theta)/g rArr R_(max)=u^2/g`
`R_(max)=(10xxgxx2)/g` = 20 metre