A particle is moving along a circular path in `xy`-plane.When its crosses `x`-axis,it has an acceleration along the path of `1.5m//s^(2)`, and is moving with a speed of `10 m//s` in `-ve` `y`-direction.The total acceleration is

Options

A. `50hati-1.5 hatj m//s^2`
B. `-50hati-1.5hatj m//s^2`
C. `10hati-1.5 hatj m//s^2`
D. `1.5 hati - 50 hatj m//s^2`

Answer

D

Explanation

`a_n=v^2/r = 10^2/2 =50 m//s^2`, along negative x-axis.
so `veca=-50 hati-1.5 hatj m//s^2`