If the equation for the displacement of a particle moving in a circular path is given by `(theta)=2t^(3)+0.5`, where `theta` is in radians and `t` in seconds, then the angular velocity of particle after `2 s` from its start is

Options

A. 8 rad/s
B. 12 rad/s
C. 24 rad/s
D. 36 rad/s

Answer

C

Explanation

`omega=(d theta)/(dt)=(d(2t^3+0.5))/(dt)=3xx2t^2 =6(2)^2`=24 rad/s