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The kinetic energy of partical moving al...

The kinetic energy of partical moving along a circule of radius `R` depends upon the distance covered `S` and given by `K = aS` where `a` is a constant. The the force acting on the partical is

A

`(aS)/(R )`

B

`(2(aS)^(2))/(R )`

C

`(aS^(2))/(R^(2))`

D

`(2aS)/(R)`

Text Solution

Verified by Experts

The correct Answer is:
D
Centripetal Force `=(mv^(2))/(R )=((1)/(2)mv^(2))(2)/(R )=(2K)/(R )=(2aS)/(R )`
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