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A mass of M kg is suspended by a weightl...

A mass of M kg is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of `45^@` with the initial vertical direction is

A

Mg(`sqrt(2+1)`

B

Mg`sqrt(2)`

C

`(Mg)/sqrt(2)`

D

Mg(`sqrt(2)`-1)

Text Solution

Verified by Experts

The correct Answer is:
D
Work done by force (applied)+work done by gracitational force=change in kinetic enery
`impliesxxAB-Mg AC=0`
`impliesF=Mg((AC)/(AB))=Mg[((1-(1))/(sqrt(2)))/((1)/sqrt(2))]`
Mg`(sqrt(2)-1)`
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