A body of mass m accelerates uniformly from rest to `v_1` in time `v_2`. As a function of time t, the instantaneous power delivered to the body is

Options

A. `(mv_(1)t)/(t_(1)^(2))`
B. `(mv_(1)^(2)t)/(t_(1))`
C. `(mv_(1)^(2)t)/(t_(1))`
D. `(mv_(1)^(2)t)/(t_(1)^(2))`

Answer

D

Explanation

From v=u+at,`v_(1)0+at_(1)`
`therefore a=(v_(1))/(t_(1)) F=ma=mv_(1)//t_(1)`
Velocity acquired in t sec=at `=(v_(1))/(t_(1))t`
Power`=Fxxv=(mv_(1))/(t_(1))xx(v_(1)t)/(t_(1))=(mv_(1)^(2)t)/(t_(1)^(2))`