An engine pumps water continously through a hose. Water leave the hose with a velocity `v` and `m` is the mass per unit length of the Water jet. What is the rate at Which kinetic energy is imparted to water?

Options

A. `mv^(2)`
B. `(1)/(2)mv^(2)`
C. `(1)/(2)m^(2)v^(2)`
D. `(1)/(2)mv^(3)`

Answer

D

Explanation

m:mass per unit length `therefore` rate of mass leaving the the hose per sec`(mx)/(t)=mv`.
Rate of K.E.=`(1)/(2)` (mv)`v^(2)=(1)/(2)mv^(3)`