A force applied by an engine of a train ...

A force applied by an engine of a train of mass `2.05xx10^6`kg changes its velocity from 5 m/s to 25 m/s in 5 minutes. The power of the engine is

1.025 MW

2.05 MW

5 MW

6 MW

Text Solution

Verified by Experts

The correct Answer is:

`Power=("Work done")/("Time")=((1)/(2)m(v^(2)-u^(2)))/(t)`
`P=2.05xx10^(6)W=2.05 MW`

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