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An elevator can carry a maximum load of ...

An elevator can carry a maximum load of `1800 kg` (elevator + passengers) is moving up with a constant speed of `2 ms^(-1)`. The friction force opposite the motion is `4000 N`.What is minimum power delivered by the motor to the elevator?

A

59 hp

B

22hp

C

34hp

D

44hp

Text Solution

Verified by Experts

The correct Answer is:
D
P=Fv=`(1800g+4000)xx2`=44000W.
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