A particle initially at rest on a frictionless horizontal surface, is acted upon by a horizontal force which is constant is size and direction. A graph is plotted between the work done (W) on the particle, against the speed of the particle, (v). If there are no other horizontal forces acting on the particle the graph would look like

Options

A.
B.
C.
D.

Answer

C

Explanation

According to work energy theorem
`W=(1)/(2)mv^(2)-(1)/(2)mu^(2)=(1)/(2)mv^(2)(because u=0)`
`impliesWpropv^(2)`