A block of mass 5.0 kg is suspended from the end of a vertical spring which is stretched by 10 cm under the load of the block. The block is given a sharp impulse from below so that it acquires an upward speed of 2.0 m/s. How high will it rise? Take `g=10 m/s^2`

Options

A. 0.10m
B. 0.20m
C. 0.25m
D. None of these

Answer

B

Explanation

`(1)/(2)m(2)^(2)+(1)/(2)k(0.1)^(2)`
`=mgh+(1)/(2)k(h-0.1)^(2)`
After solving ,we get h=0.2 m