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One end of an unstretched vertical sprin...

One end of an unstretched vertical spring is attached to the ceiling and an object attached to the other end is slowly lowered to its equilibrium position. If S is the gain in spring energy and G is the loss in gravitational potential energy in the process, then

A

S=G

B

S=2G

C

G=2S

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C

At equilibrium position ,`x=(mg)/(k)`
`U_("spring")=(1)/(2)kx^(2)=(1)/(2)((mg)/(k))x`
`=(mgx)/(2)=(1)/(2)`(loss in GPE)`implies`G=2S
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