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A charged particle with a velocity 2xx10...

A charged particle with a velocity `2xx10^(3) ms^(-1)` passes undeflected through electric field and magnetic fields in mutually perpendicular directions. The magnetic field is `1.5 t. the magnitude of electric field will be

A

`2xx10^3N//C`

B

`1.5xx10^3N//C`

C

`3xx10^3N//C`

D

`4//3xx10^(-3)N//C`

Text Solution

Verified by Experts

The correct Answer is:
C
`E = vB = 2xx 10^(3) xx 1.5 =3xx10^3N//C`
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