`3 A` of current is flowing in a linear conductor having a length of `40 cm`. The conductor is placed in a magnetic field of strength 500 gauss and makes an angle of `30^(@)` with the direction of the field. It experiences a force of magnitude

Options

A. `3xx10^(-4)N`
B. `3xx10^(-2)N`
C. `3xx10^2N`
D. `3xx10^4N`

Answer

B

Explanation

`F = IlB sin theta = 3 xx0.40 xx(500xx 10^(-4))xx sin 30^@ = 3 xx 10 ^(-2)N` .