Lights of wavelength 550 nm falls normally on a slit of width k`22.0 xx 10^(-5) cm`. The angular position of the central maximum will be (in radian) :

Options

A. `pi/8`
B. `pi/12`
C. `pi/4`
D. `pi/6`

Answer

A

Explanation

If angular position of `2^(nd)` maxima from central maxima is `theta` then
`sintheta=((2n-1)lamda)/(2a)=(3lamda)/20=(3xx550xx10^(-9))/(2xx22xx10^(-7))" "thereforetheta=pi/8"rad"`