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Two coherent monochromatic light beams o...

Two coherent monochromatic light beams of intensities I and `4I` are superposed. The maximum and minimum possible intensities in the resulting beam are

A

5I and I

B

5I and 3I

C

9I and I

D

9I and 3I

Text Solution

Verified by Experts

The correct Answer is:
C

`I_(max)=I+4I+2sqrt(Ixx4I)=9I`,
and `I_(min)=I+4I-2sqrt(Ixx4I)=I`.
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DISHA PUBLICATION-WAVE OPTICS-EXERCISE-1 : CONCEPT BUILDER
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  2. Interference pattern is observed at 'P' due to superimposition of two ...

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  3. Two coherent monochromatic light beams of intensities I and 4I are sup...

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  4. The path difference between two interfering waves at a point on screen...

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  5. For the two parallel rays AB and DE shown here, BD is the wavefront. F...

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  6. In the adjacent diagram, CP represents a wavefront and AO & BP, the co...

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  7. Two beam of light having intensities I and 4I interfere to produce a f...

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  8. Light from two coherent sources of the same amplitude A and wavelength...

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  9. A point p is situated 90.50cm and 90.58 cm away from two coherent sour...

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  10. For observing interference in thin films with a light of wave length l...

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  11. Sodium light (lambda= 6xx 10^(-7)m) is used to produce interference pa...

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  12. In which of the following is the interference due to the division of w...

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  13. In Young's double slit experiment, one slit is covered with red filter...

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  14. In Young's double slit experiment, a minimum is obtained when the phas...

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  15. Instead of using two slits as in Young's experiment, if we use two sep...

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  16. The maximum intensity of fringes in Young's experiment is I. If one of...

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  17. When we close one slit in the Young's double slit experiment then

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  18. S is the size of the slit, d is the separation between the slits and D...

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  19. Distance between screen and source is decreased by 25%. Then the perce...

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  20. In a Young’s double slit experiment, the separation of the two slits i...

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