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In YDSE, bichromatic light of wavelength...

In YDSE, bichromatic light of wavelengths 400 nm and 560 nm
are used. The distance between the slits is 0.1 mm and the distance between the
plane of the slits and the screen is 1m. The minimum distance between two
successive regions of complete darkness is

A

4mm

B

5.6mm

C

14mm

D

28mm

Text Solution

Verified by Experts

The correct Answer is:
D

For dark fringes of both waves at same place
`y_(1)=y_(2)`
`(n+1)(Dlamda_(1))/d=n(Dlamda_(2))/d`
or `(n+1)xx400=nxx560`
or n = 2.5, and n + 1 = 3.5
There integer value is 5 and 7.
The distance between two regions of complete dark,
`Deltax=7(Dlamda)/d=(7xx1xx400xx10^(-9))/(0.1xx10^(-3))=28mm`.
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DISHA PUBLICATION-WAVE OPTICS-EXERCISE-1 : CONCEPT BUILDER
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  14. Unpolarized light is incident on a plane sheet on water surface. The a...

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  15. The fraunhofer diffraction pattern of a single slit is formed at the f...

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  16. Unpolarised light of intensity 32 Wm^(-2) passes through three polariz...

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  17. A parallel beam of light of wavelength l is incident normally on a nar...

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