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In Young's double slit experiment, dista...

In Young's double slit experiment, distance between two sources is 0.1mm. The distance of screen from the sources is 20cm. Wavelength of light used is `5460 Å`. Then, angular position of first dark fringe is approximately

A

`0.08^(@)`

B

`0.16^(@)`

C

`0.20^(@)`

D

`0.32^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B

The position of `n^(th)` dark fringe. So position of first dark fringe in `x_(1)=lamdaD//2d`.
`d=20cm,D=0.1mm,lamda=5460Å,x_(1)=0.16^(@)`
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