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A beam of light of lambda = 600 nm from ...

A beam of light of `lambda` = 600 nm from a distant source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2 m away. The distance between first dark fringes on either side of the central bright fringe is

A

1.2 cm

B

1.2 mm

C

2.4 cm

D

2.4 mm

Text Solution

Verified by Experts

The correct Answer is:
D

Given: `D=2m,d=1mm=1xx10^(-3)m`
`lamda=600nm=600xx10^(-6)m`
Width of central bright fringe `(=2beta)`
`=(2lamdaD)/d=(2xx600xx10^(-6)xx2)/(1xx10^(-3))m=2.4mm`
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