In a Young's double slit experiment, if the incident light consists of two wavelengths `lamda_(1)andlamda_(2)`, the slit separation is d, and the distance between the slit and the screen is D, the maxima due to the two wavelengths will coincide at a distance from the central maxima, given by :

Options

A. `(lamda_(1)lamda_(2))/(2Dd)`
B. `(lamda_(1)-lamda_(2))*(2d)/D`
C. LCM of `lamda_(1)*D/dandlamda_(2)*D/d`
D. HCF of `(lamda_(1)D)/dand(lamda_(2)D)/d`

Answer

C

Explanation

`y_(n)=(nDlamda_(1))/d=((n+1)Dlamda_(2))/dorn=((lamda_(2))/(lamda_(2)-lamda_(1)))`
and `y_(n)=((lamda_(1)lamda_(2))/(lamda_(2)-lamda_(1)))(D/d)`.