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The central fringe of the interference p...

The central fringe of the interference pattern produced by the light of wavelength 6000 Å is found to shift to the position of 4th dark fringe after a glass sheet of refractive index 1.5 is introduced. The thickness of glass sheet would be

A

`4.8mum`

B

`8.23mum`

C

`14.98mum`

D

`3.78mum`

Text Solution

Verified by Experts

The correct Answer is:
A
Shift = `D/d(mu-1)t=beta/lamda(mu-1)t=4beta`
`t=(4lamda)/(mu-1)=(4xx6000xx10^(-10))/(1.5-1)=4.8mum`
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