In a double slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic light of wavelength 500 mm is used.what will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single slit pattern?

Options

A. 0.1 mm
B. 0.5 mm
C. 0.02 mm
D. 0.2 mm

Answer

D

Explanation

Here, distance between two slits,
`d=1mm=10^(-3)m`
distance of screen from slits, D = 1m
wavelength of monochromatic light used,
`lamda=500nm = 500xx10^(-9)m`
width of each slit a = ?
Width of central maxima in single slit pattern = `(2lamdaD)/a`
Fringe width in double slit experiment `beta=(lamdaD)/d`
So, required condition `(10lamdaD)/d=(2lamdaD)/a`
`rArra=d/(5D)=1/5xx10^(-3)m=0.2mm`