In Young's double slit experiment, wavelength `lambda=5000Å` the distance between, the slits is `0.2mm` and the screen is at 200cm from the slits. The central maximum is at `x=0` The third maximum (Taking the central maximum as zeroth maximum) will be at x equal to

Options

A. 1.67 cm
B. 1.5 cm
C. 0.5 cm
D. 5.0 cm

Answer

B

Explanation

`x=(n)lamdaD/d=3xx5000xx10^(-10)xx2/(0.2xx10^(-3))`
= `1.5xx10^(-2)m=1.5cm`