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Light of wavelength 6328Å is incident no...

Light of wavelength `6328Å` is incident normally on slit having a width of `0.2mm`The width of the central maximum measured form minimum to minimum of diffraction pattens on a screen `9.0meter`away will be about-

A

0.36 degree

B

0.18 degree

C

0.72 degree

D

0.09 degree

Text Solution

Verified by Experts

The correct Answer is:
A
The angular width of central maxi is
`2theta=2lamda/a=(2xx6328xx10^(-10))/(2xx10^(-4))` radian.
= `6328xx10^(-6)xx180/pi"degree"=0.36^(@)`
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