A particle is executing simple harmonic motion (SHM) of amplitude A, along the x-axis, about x = 0. When its potential Energy (PE) equals kinetic energy (KE), the position of the particle will be :
A particle executes simple harmonic motion of ampliltude A. At what distance from the mean position is its kinetic energy equal to its potential energy?
A particle is executing simple harmonic motion with amplitude A. When the ratio of its kinetic energy to the potential energy is (1)/(4) , its displacement from its mean position is
A particle executes simple harmonic motion of amplitude A along the x - axis. At t = 0 , the position of the particle is x = (A)/(2) and it moves along the positive x - direction. Find the phase contant delta , if of the equation is written as x = Asin (omega t + delta) .
A particle is executing linear simple harmonic motion of amplitude 'A'. The fraction of the total energy is the kinetic when the displacement is half of the amplitude is
A particle executes simple harmonic motion of amplitude A (i) At what distance from the extreme positino is its kinetic energy equal to half its potential energy ? (ii) At what position from the extreme position is its speed half the maximum speed.
When the displacement of a particle executing simple harmonic motion is half its amplitude, the ratio of its kinetic energy to potential energy is
A particle is executing simple harmonic motion with frequency f . The frequency at which its kinetic energy changes into potential energy is
