A parallel plate capacitor with square plates is filed with four dielectrics of dielectric constants `K_(1),K_(2),K_(3),K_(4),` arranged as shown in the figure. The effective dielectric constant K will be :
The space between parallel plate capacitors is filled with four dielectrics of equal dimensions but of dielectric constants K_(1), K_(2), K_(3)andK_(4) respectively. If K is the dielectric constant of a single dielectric that must be filled between capacitor plates to have the same capacitance between A and B. Then we must have
A parallel -plate capacitor of area A , plate separation d and capacitance C is filled with four dielectric materials having dielectric constant k_(1), k_(2), k_(3) and k_(4) as shown in the figure below. If a single dielectric materical is to be used to have the same capacitance C in this capacitor, then its dielectric constant k is given by
A parallel plate capacitor of area A , plate separation d and capacitance C is filled with three different dielectric materials having dielectric constant K_(1),K_(2) and K_(3) as shown in fig. If a single dielectric material is to be used to have the same effective capacitance as the above combination then its dielectric constant K is given by :
A parallel plate capacitor of area A, plate separation d and capacitance C is filled with three different dielectric materials having dielectric constants k_1 , k_2 and k_3 as shown. If a single dielectric material is to be used to have the same capacitance C in this capacitor, then its dielectic constant k is given by
A parallel plate capacitor of area A, plate separation d and capacitance C is filled with three different dielectric materials having dielectric constants k_1 k_2 and k_3 as shown in the following figure. If a single dielectric material is to be used to have the same capacitance C in this capacitor then its dielectric constant k is given by
