Four equal point charges Q each are placed in the xy plane at (0,2), (4,2), (4,-2) and (0, -2)`. The work required to put a fifth charge Q at the origin of the coordinate system will be
Two point charges of +Q each have been placed at the positions (–a//2, 0, 0) and (a//2, 0, 0) . The locus of the points in YZ plane where –Q charge can be placed such the that total electrostatic potential energy of the system can become equal to zero, is represented by which of the following equations ?
Consider two positive point charges, each of magnitude q, placed on the y-axis at the points (0, a) and (0, -a). A positively charged particle of charge q' and mass m is displaced slightly from the origin in the direction of the positive x-axis. At the origin, charge q' will be in
Two point charges (Q each are placed at (0,y) and (0-y) A point charge q of the sme polarity can move along the x-axis. Then
Consider two positive point charges, each of magnitude q, placed on the y-axis at the points (0, a) and (0, -a). A positively charged particle of charge q' and mass m is displaced slightly from the origin in the direction of the positive x-axis. Speed of charge q' at infinity is
Four equal charges Q are placed at the four corners of a square of each side is 'a'. Work done in removing a charge -Q from its centre to infinity is
Four charges +q,+q-q, and -q are placed on X - Y plane at the points whose coordinates are (0.5, 0), (0, 0.5), (-0.5, 0) and (0, -0.5) respectively. The electric field due to these charges at a point P(r,r), where r gtgt 0. 5 , will be
Consider two point charges q_(1)=q_(2)=q(qgt0) placed in x-y plane at (0,-R) and (R,0) as shown in the figure. Now charges q_(2) starts revolving in anticlockwise sense with uniform angular velocity omega in a circle about origin in xy-plane. E is magnitude of net field at origin, V is potential at origin and E_(x) is x-component of field at origin then select correct variation of V,E_(x) and E with time t.
IT si required to hold four equal point charges each having a charge Q=(8)/(7)(1-2sqrt(2))C in equilibrium at the corners of a square.Find the point charge in coulombs that will do this if placed at the centre of the square.
Two point charges q each are fixed at (a,0) and (-a,0). A third charge Q is placed at origin. Electrons potential energy of the system will
