A body is project at t= 0 with a velocity `10 ms^-1` at an angle of `60 ^(@)` with the horizontal .The readius of curvature of its trajectory at t=1s is R. Neglecting air resitance and taking acceleration due to gravity `g= 10 ms^-2`, the value of R is :
A stone is projected with speed of 50 ms^(-1) at an angle of 60^(@) with the horizontal. The speed of the stone at highest point of trajectory is
A particle is projected with velocity 20 ms ^(-1) at angle 60^@ with horizontal . The radius of curvature of trajectory , at the instant when velocity of projectile become perpendicular to velocity of projection is , (g=10 ms ^(-1))
A body is projected down from height of 60 m with a velocity 10 ms ^(-1) at angle 30^(@) to horizontal. The time of flight of the body is [g = 10 ms ^(-2)]
A body is projected with a velocity 60 ms ^(-1) at 30^(@) to horizontal . Its initial velocity vector is
A projectile thrown with an initial velocity of 10 ms^(-1) at an angle with the horizontal, has a range of 5 m. Taking g=10 ms^(-2) and neglecting air resistance, what will be the estimated value of alpha ?
A particle is projected with a speed 10sqrt(2) ms^(-1) and at an angle 45^(@) with the horizontal. The rate of change of speed with respect to time at t = 1 s is (g = 10 ms^(-2))
A body is projected with a velocity of 20 ms^(-1) in a direction making an angle of 60^(@) with the horizontal. Determine its (i) position after 0.5 s and (ii) the velocity after 0.5s .
A body is projected with a velocity 40ms^(-1) at 30^(0) to horizontal.Its initial velocity vector is
A body is projected at angle 30^(@) to horizontal with a velocity 50 ms^(-1) .Its time of flight is
