The force of interaction between two atoms is given by `F= alpha beta exp(-(x^2)/(alphakt))` , where x is the distance ,k is the Boltzmann constant and T is temperature and `alpha " and " beta` are two constans. The dimension of `beta` is :
The workdone by a gas molecule in an isolated system is given by, W = alpha beta^2 e^( - (x^2)/(alpha k T) ) , where x is the displacement, k is the Boltzmann constant and T is the temperature, alpha and beta are constants. Then the dimension of B will be :
In a typical combustion engine the work done by a gas molecule is given W=alpha^2betae^((-betax^2)/(kT)) where x is the displacement, k is the Boltzmann constant and T is the temperature. If alpha and beta are constants, dimensions of alpha will be:
In the releation p=(alpha)/(beta) e^(-)(az)/(ktheta) , where p is the pressure z is distance k is Boltzmann constant and theta is the temperature the dimensional formula beta will be
In the relation P = (alpha)/(beta) e^((alpha Z)/(k theta)) , P is pressure, Z is height, k is Boltzmann constant and theta is the temperature. Find the dimensions of alpha and beta
In the relation, P=alpha/beta e^((alphaZ)/(ktheta))P is pressure, Z is distance, k is Boltzmann constant and theta is the temperature. The dimensional formula of beta will be-
Pressure depends on distance as, P = (alpha)/(beta)exp((-alpha z)/(k theta)) , where alpha, beta are constants, z is distance, k is Boltzmann's constant and theta is temperature. The dimensions of beta are :
Pressure depends on distance as, P = (alpha)/(beta)exp(-(alphaz)/(ktheta)) , where alpha, beta are constants, z is distance as , k is Boltzman's constant and theta is tempreature. The dimension of beta are
In the equation ((1)/(pbeta))=(y)/(k_(B)T) , where p is the pressure, y is the distance, k_(B) is Boltzmann constant and T is the tempreture. Dimensions of beta are
F=alphabetae^((-(x)/(alphakt))) k = Boltzmann constant t = temperature x = distance The dimensions of B is
