`Ice at -20^(@)C` is added to 50 g of water at `40 ^(2)C` When the temperature of the mixture reaches `0^(@) C` it is found that 20 g of ice is still unmelted .The amount of ice added to (Specific heat of water `=4.2 j//g//^(@)C` Specific heat of Ice `=2.1 J//g //^(@)C` M Heat of fusion of water of `0^(@)C=334 J//g)`
Ice at 20^(@)C is added to 50 g of water at 40^(@) . When the temperaurtre of the mixture reaches 0^(@)C , it is observed that 20 g of ice is still unmelted. The amount (in gram) of ice added to the water was (Specific heat of water =4.2J//g//""^(@)C Specific heat of ice =2.1J//g//""^(@)C Heat of fusion of water at 0^(@)C=334J//g)
10 g ice at 0^(@)C is mixed with 20 g of water at 20^(@)C . What is the temperature of mixture?
If 2g ice at 0^(0)C is dropped into 10g water at 80^(0)C then temperature of mixture is
5 g of ice at 0^@C and 20 g of water at 45^@C are mixed. The temperature of the mixture will be
Ice at -20^(@)C mixed with 200g water at 25^(@)C . If temperature of mixture is 10^(@)C then mass of ice is -
X g of ice at 0 .^(@)C is added to 340 g of water at 20^(@)C. The final tempeature of the resultant mixture is 5 .^(@)C. The value of X (in g) is closest to [Heat of fusion of ice = 333 J//g, Specific heat of water = 4.184 J//g. K ]
