A proton and an `alpha -` Particle ( with their masses in the ratio of 1:4 and charges in the ratio of 1:2 ) are accelerated form rest through a potential differeence V, if a uniform magnetic field (B) is set up perpendicular to their velocities , the ratio of the radii `r_(p) : r_(alpha)` of the circular paths described by them will be :
Two charged particles 'A' and 'B' (with their masses in the ratio of 2:3 and charges in the ratio 1:2 are accelerated from rest through a potential difference V.If a uniform magnetic field (B) is set up perpendicular to their velocities,the ratio of the radii rA:rB of the circular paths described by them will be:
A charged particle of mass m and charge q is accelerated through a potential differences of V volts. It enters of uniform magnetic field B which is directed perpendicular to the direction of motion of the particle. The particle will move on a circular path of radius
The ratio of moment of an electron and an alpha -particle which are accelerated from rest by a potential difference of 100V is
A charged particle of mass m and charge q is accelerated through a potential difference of V volts. It enters a region of uniform magnetic field which is directed perpendicular to the direction of motion of the particle. Find the radius of circular path moved by the particle in magnetic field.
A proton is accelerated through a potential difference V, subujected to a uniform magnetic field acting normal to the velocity of the proton. If the potential difference is doubled, how will the radius of the circular path described by the proton in the magnetic field charge ?
A proton and an alpha -particle, accelerated through same potential difference, enter a region of uniform magnetic field with their velocities perpendicular to the field. Compare the radii of circular paths followed by them.
