Home
Class 12
PHYSICS
In the figure shown , after the switch ...

In the figure shown , after the switch 's' is turned from postion 'A' to postion 'B' the energy dissipated in the circuit in terms of capactance 'C' and total charge 'Q' is :

A

`(1)/(8) (Q^(2))/(C)`

B

`(3)/(8) (Q^(2))/(C)`

C

`(5)/(8) (Q^(2))/(C)`

D

`(3)/(4) (Q^(2))/(C)`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • JEE MAINS

    JEE MAINS PREVIOUS YEAR|Exercise Chemistry|1 Videos
  • JEE MAIN 2024 ACTUAL PAPER

    JEE MAINS PREVIOUS YEAR|Exercise Question|522 Videos
  • JEE MAINS 2020

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS|246 Videos

Similar Questions

Explore conceptually related problems

Find heat dissipated in the circuit after switch S in closed. C = 2 muF .

Refer to Fig. 7.49 . Now the switch is opened after closing it for a long time. Find the total energy dissipated in the system.

In the circuit as shown in the figure, switch S is added at t=0. Then:

In the circuit shown in the figure, the switch S is in position 1 for a long time. Now the switch is thrown to position 2. Find the total heat developed in the circuit till the steady state is reached again.

A capacitor of 2 mu F is charged as shown in the diagram. When the switch S is turned to position 2, the percentage of its stored energy dissipated is:

Find the charge flown through the path 1, 2, 3 as shown in figure after closing switch S and heat generated in the circuit.