In the value circuit, `C=(sqrt(3))/(2)muF,R_2=20omega, L=sqrt(3)/(10)H`, and `R_1=10omega` .Current in `L-R_1` path is `I_1` and in `C-R_2` path it is `I_2`. The voltage of A.C source is given by, `V=200sqrt(2)sin(100t)` volts. The phase difference between `I_2` and `I_1` is :
In the circuit shown in figure : R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega and C = (sqrt(3))/(2) mF . Current in L - R_(1) circuit is I_(1) in C - R_(1) circuit is I_(2) and the main current is I Phase difference between I_(1) and I_(2) is
A 200 Omega resistor and 1H inductor are joined in series with an ac source of emf 10 sqrt(2) sin (200t)V . Calculate the phases difference between emf and current.
200 Omega resistance and 1H inductance are connected in series with an A.C. circuit. The frequency of the source is (200)/(2pi) Hz. Then phase difference in between V and I will be-
In the circuit shown in figure : R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega and C = (sqrt(3))/(2) mF . Current in L - R_(1) circuit is I_(1) in C - R_(1) circuit is I_(2) and the main current is I At some instant current in L - R_(1) circuit is 10 A . At the same instant current in C - R_(2) branch will be
In the circuit shown in figure : R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega and C = (sqrt(3))/(2) mF . Current in L - R_(1) circuit is I_(1) in C - R_(1) circuit is I_(2) and the main current is I At some instant I_(1) in the circuit is 10 sqrt(2) A , then at this instant current I will be
In the following circuit , E_1 = 4V, R_1 = 2 Omega, E_2 = 6 V, R_2 = 2Oemga, and R_3 = 4Omega. Find the currents i_1 and i_2
In an L-R circuit, an inductance of 0.1 H and a resistance of 1 Omega are connected in series with an ac source of voltage V = 5 sin 10 t. The phase difference between the current and applied voltage will be
In an L-R circuit, an inductance of 0.1 H and a resistance of 1 Omega are connected in series with an ac source of voltage V = 5 sin 10 t. The phase difference between the current and applied voltage will be
For a series RLC circuit R=X_(L)=2X_(C) . The impedance of the current and phase different (between) V and i will be
