In a radioactive decay chain, the initial nucleus is `overset(232)(90).^(Th)`. At the end there are 6 `alpha`-particles and 4 `beta`-particles which are emitted. If the end nucleus is `overset(A)(Z).^(X),A` and Z are given by :
A nucleus ._n^ m X emits one alpha- particle and two beta- particles. The resulting nucleus is
._(92)U^(238) emits 8 alpha- particles and 6 beta- particles. The n//p ratio in the product nucleus is
A nucleus ._(Z)X^(A) emits 2 alpha - particles and 3 beta - particles. The ratio of total protons and neutrons in the final nucleus is :
How many alpha and beta -particles are emitted when uranium nucleus (._(92)U^(238)) decay to ._(82)Pb^(214) ?
A uranium nucleus ._(92)U^(238) emits and alpha -particle and a beta -particle in succession. The atomic number and mass number of the final nucleus will be
Radioactive nuclei emit beta^-1 particles. Electrons exist inside the nucleus.
How may alpha- and beta- particles will be emitted when ._(90)Th^(232) changes into ._(82)Pb^(208) ?
