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The vector equation of the line (x-2)/(2...

The vector equation of the line `(x-2)/(2)=(2y-5)/(-3),z=-1` is `r=(2hati+(5)/(2)hatj-hatk)+lambda(2hati-3/2hatj+xhatk)` where x is equal to

A

0

B

1

C

2

D

2

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The vector equation of the line (x-5)/(3) = ( y +4)/(7) = (z-6)/(2) is vecr = 5 hati - 4 hatj + 6 hatk + lamda( 3 hati + 7 hatj + 2hatk)

The vector equation of the line passing through a point with position vector 2hati-hatj+hatk and parallel to the line joining the points with position vectors -hati+4hatj+hatk and hati+2hatj+2hatk is r=(2hati-hatj+hatk)+lambda(xhati-2hatj+hatk) where x is equal to

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Find the vector and catesian equations of the plane containing the lines : vec(r) = 2 hati + hatj - 3 hatk + lambda (hati + 2 hatj + 5 hatk ) and vec(r) = 3 hati + 3 hatj - 7 hatk + mu (3 hati - 2 hatj + 5 hatk ) .

Find the vector and Cartesian equations of a plane containing the two lines vecr=(2hati+hatj-3hatk)+lambda(hati+2hatj+5hatk) and vecr=(3hati+3hatj+2hatk)+mu(3hati-2hatj+5hatk) .

Find the vector and cartesian equations of the plane containing the lines : vec(r) = hati + 2 hatj - 4 hatk + lambda (2 hati + 3 hatj + 6 hatk) and vec(r) = 3 hati + 3 hatj - 5 hatk + mu (-2 hatj + 3 hatj + 8 hatk) .

Find the vector and Cartesian forms of the equationi of the plane containing the two lines. vecr=(hati+2hatj-4hatk)+lambda(2hati+3hatj+6hatk) and vecr=(9hati+5hatj-hatk)+mu(-2hati+3hatj+8hatk) .

DISHA PUBLICATION-THREE DIMENSIONAL GEOMETRY -Exercise -1 : Concept Builder (Topicwise)
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  17. If a line with direction ration 2: 2: 1 intersects the lines (x-7)/3=(...

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