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From the point (1,-2,3) lines are drawn ...

From the point (1,-2,3) lines are drawn to meet the sphere `x^2+y^2+z^2=4` and they are divided internally in the ratio 2 : 3 . The locus of the point of division is

A

`5x^2+5y^2+5z^2 - 6 x + 12y + 22=0`

B

`5(x^2+y^2+z^2)=22`

C

`5x^(2) +5y^2+5z^2-2xy-3yz -zx-6x +12y + 5y +22=0`

D

`5x^2+5y^2+5z^2-6x +12y +18z +22=0`

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The correct Answer is:
To find the locus of the point of division of the lines drawn from the point \( P(1, -2, 3) \) to the sphere defined by the equation \( x^2 + y^2 + z^2 = 4 \), which are divided internally in the ratio \( 2:3 \), we can follow these steps: ### Step 1: Define the Points Let \( Q(x_1, y_1, z_1) \) be a point on the sphere. The coordinates of \( Q \) must satisfy the equation of the sphere: \[ x_1^2 + y_1^2 + z_1^2 = 4 \] ### Step 2: Use the Section Formula The coordinates of the point \( D(x_2, y_2, z_2) \) that divides the segment \( PQ \) in the ratio \( 2:3 \) can be found using the section formula. The coordinates are given by: \[ x_2 = \frac{3x_1 + 2 \cdot 1}{2 + 3} = \frac{3x_1 + 2}{5} \] \[ y_2 = \frac{3y_1 + 2 \cdot (-2)}{2 + 3} = \frac{3y_1 - 4}{5} \] \[ z_2 = \frac{3z_1 + 2 \cdot 3}{2 + 3} = \frac{3z_1 + 6}{5} \] ### Step 3: Substitute \( x_1, y_1, z_1 \) in terms of \( x_2, y_2, z_2 \) From the equations for \( x_2, y_2, z_2 \), we can express \( x_1, y_1, z_1 \): \[ 3x_1 = 5x_2 - 2 \implies x_1 = \frac{5x_2 - 2}{3} \] \[ 3y_1 = 5y_2 + 4 \implies y_1 = \frac{5y_2 + 4}{3} \] \[ 3z_1 = 5z_2 - 6 \implies z_1 = \frac{5z_2 - 6}{3} \] ### Step 4: Substitute into the Sphere Equation Now substitute these expressions into the sphere equation: \[ \left(\frac{5x_2 - 2}{3}\right)^2 + \left(\frac{5y_2 + 4}{3}\right)^2 + \left(\frac{5z_2 - 6}{3}\right)^2 = 4 \] Multiplying through by \( 9 \) (to eliminate the denominators): \[ (5x_2 - 2)^2 + (5y_2 + 4)^2 + (5z_2 - 6)^2 = 36 \] ### Step 5: Expand and Simplify Expanding each term: \[ (5x_2 - 2)^2 = 25x_2^2 - 20x_2 + 4 \] \[ (5y_2 + 4)^2 = 25y_2^2 + 40y_2 + 16 \] \[ (5z_2 - 6)^2 = 25z_2^2 - 60z_2 + 36 \] Combining these: \[ 25x_2^2 + 25y_2^2 + 25z_2^2 - 20x_2 + 40y_2 - 60z_2 + 56 = 36 \] Simplifying: \[ 25x_2^2 + 25y_2^2 + 25z_2^2 - 20x_2 + 40y_2 - 60z_2 + 20 = 0 \] ### Step 6: Divide by 5 Dividing the entire equation by 5 gives: \[ 5x_2^2 + 5y_2^2 + 5z_2^2 - 4x_2 + 8y_2 - 12z_2 + 4 = 0 \] ### Final Locus Equation The locus of the point of division \( D(x_2, y_2, z_2) \) is: \[ 5x^2 + 5y^2 + 5z^2 - 4x + 8y - 12z + 4 = 0 \]
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